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April 29, 2008 12:00 AM

The Logical Puzzle

SQL Server Pro
InstantDoc ID #98361

Solution to April’s Puzzle: Suicidal Mosquito
Two trains drive toward each other on the same rail. Both trains drive at a speed of 100MPH. When the trains are 100 miles apart, a mosquito starts flying back and forth from the front of one train to the other at a speed of 200MPH. What total distance will the mosquito cover before the two trains crash?

For some people the puzzle might seem to require infinity calculations. Although solving the puzzle this way is possible, such a solution is unnecessarily complicated. The simplest way to think about the puzzle is to consider only duration and speed. The time it takes until the trains crash is half an hour, and the speed of the mosquito is 200MPH. With such speed and duration, the mosquito would cover 100 miles.

May’s Puzzle: A Cat, a String, and the Earth
This month’s puzzle is quite simple, but I like it because it’s so counter intuitive. Suppose you lay a string on the ground all around the earth right over the equator. The length of the string would be equal to the earth’s equatorial circumference—40,075.02 kilometers. Then, suppose you add 1 meter to the string, and suspend the string directly above the equator, with an even distance from the ground all the way around. Would a cat be able to pass from one hemisphere to another below the string?



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Comments
  • Thomas
    4 years ago
    Jun 14, 2008

    It really depends on the direction the cat is traveling. One way the cat will drown. The other way the cat will need to be able to pass under .4 meters or approx. 15 3/4 in. (an isosceles triangle that represents the added meter can be used to estimate the max height of the cat, the total of the longest legs being 1 meter, each is therefore .5 meters, making the height .4 meters by way of two pythagorean 3,4,5s)

    North to south passing is plausible (a grown lion might not be able to though); west to east is rather not possible, and drowning cats is sad.

  • marius
    4 years ago
    May 14, 2008

    A cat can easily pass between the hemisphere now when the second string is 15.9 cm (6.2 inch) over the first string.

  • SEAN
    4 years ago
    May 13, 2008

    Super fun

  • KEN
    4 years ago
    May 09, 2008

    Here's what I think is interesting. What if you repeated the experiment on Jupiter? Pretend Jupiter has a solid surface and the cat has a space suit.

  • John
    4 years ago
    May 07, 2008

    You forget that the change in diameter does not equate directly to change in height of the string. The height the string changes is related to the radius, half the diameter, or 15.9cm. Still, the average cat could slink under on its belly.

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