Listing A: Solving the Kids' Ages
WITH
  L0 AS(SELECT 0 AS c UNION ALL SELECT 0),
  L1 AS(SELECT 0 AS c FROM L0 AS a, L0 AS b),
  L2 AS(SELECT 0 AS c FROM L1 AS a, L1 AS b),
  L3 AS(SELECT 0 AS c FROM L2 AS a, L2 AS b),
Nums AS(SELECT TOP(36) ROW_NUMBER() OVER(ORDER BY c) AS n FROM L3),
Divisors AS
(
  SELECT C1.n AS age1, C2.n AS age2, C3.n AS age3,
    COUNT(*) OVER(PARTITION BY C1.n + C2.n + C3.n) AS Cnt
  FROM Nums AS C1 CROSS JOIN Nums AS C2 CROSS JOIN Nums AS C3
  WHERE C1.n * C2.n * C3.n = 36
    AND C1.n <= C2.n AND C2.n <= C3.n
)
SELECT age1, age2, age3
FROM Divisors
WHERE Cnt > 1
  AND age3 > age2; -- One born before others (before house)
  --  AND age1 < age2; -- One born after others (after house)